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Integral Calculus

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29 Oct 2007 18:12:56 IST

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find the value of

None

^{dx/(sin(x-a)sin(x-b)sin(x-c)}

^{sin(x-a).sin(x-b).sin(x-c) all are in denominator}

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puneet

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Joined: 19 Oct 2006

Posts: 1966

6 Nov 2007 17:15:36 IST

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hiii

First divide and multiply numerator by sin(a-b) where write a-b as x - b - (x -a)

And then open the sin using sin(A - B) formula.

This simplifies the question n thn u can go ahead easily

I think it should help

cheers

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