express as e^y(f(y) + f'(y))

How it can be expressed?

please explain a little more..

Is the answer

The correct answer

Please reply me..........................

if you know what is meant by ILATE rule then you can solve this question easily.  

in ILATE,

I - inverse func

L - Logarithmic

A - Algebraic

T - Trigonometric

E - exponential

INTEGRALf(x).g(x).dx = f(x). INTEGRAL g(x)dx - {INTEGRAL[f'(x) .  INTEGRALg(x).d(x)] dx}

just replace the word INTEGRAL with the integration sign...

here you decide f(x) and g(x) in the order ILATE.  hope you understood.

a rate would be appreciated...

I think you made a mistake in typing the question.[I concluded this from your answer which is e^3x.tanx+c].Your question must have been

Now put 3x=t,then the integral will be in the form e^t[f(t)+f'(t)] where f(t)=tan(t/3).So,the integral is e^t.tan(t/3)+c=e^3xtanx+c.