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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jan 2008 11:06:44 IST
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HOE CAN WE INTEGRATE ROOT SECX WR.T. X?  ] SECX dX=?
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NISHANT PANDEY
BANSAL CLASSES,
BATCH--X4 STERLING......
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6 Jan 2008 11:15:14 IST
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integral secx(secx+tanx)/(secx+tanx)wrt dx
let u=secx+tanx
interal du/dx=natural log u log e(secx+tanx)
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> |
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6 Jan 2008 12:44:39 IST
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Substitute secx = t2
secx tanx dx = 2tdt
dx = (2t)/(t (t4-1) dt
Use this and the integral will reduce
The integral becomes
sec x dx = t (2t)/(t (t4-1) dt = (2t)/( (t4-1) dt
Assume t2 = z
2t dt = dz
(2t)/( (t4-1) dt = (1/ (z2-1))dz
Now its a standard integral ... integrate it and substitute backwards to get the final answer
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6 Jan 2008 19:46:36 IST
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NO ELESSAR! IT'S NOT END. PROBLEM NOW STARTS
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NISHANT PANDEY
BANSAL CLASSES,
BATCH--X4 STERLING......
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6 Jan 2008 19:48:17 IST
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HELLO CRACK ! IN PROBLEM ROOT SECX IS GIVEN.
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NISHANT PANDEY
BANSAL CLASSES,
BATCH--X4 STERLING......
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6 Jan 2008 19:49:36 IST
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KYA KOI ISE SOLVE KAREGA.......................................................................
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NISHANT PANDEY
BANSAL CLASSES,
BATCH--X4 STERLING......
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6 Jan 2008 19:50:37 IST
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ANSWER DE DO RATES LE LO
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NISHANT PANDEY
BANSAL CLASSES,
BATCH--X4 STERLING......
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