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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 19:58:52 IST
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hi........dis ques is of viteee......... integral 0 to infinity dx/(a^2 + x^2)^7 plzzz need a quick reply thanx
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 20:10:46 IST
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hellooooooooooo.............neone plz helpp!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 20:26:05 IST
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hi!!!!!!!!!!!!! i think ki first binomial se expand ker lo then integrate kar do......i m not sure
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 20:55:45 IST
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Put x=atanQ Then the integral becomes [0 ] [pi/2 ] cos 12QdQ*(1/a 13) =(1/a13)*{((12-1)(12-3)....)/(12(12-2)(12-4)....)}*pi/2 (Reduction formula)
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ADARSH
NITK Surathkal
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 20:59:45 IST
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hmm...........okk but tell me if dere is ne another method........wid out using reduction formula...........btw here r the options........... (A) 231/2047 a^13 (b) 235/2048 a^13 (c) 232/2047 a^13 (d) 231/2048 a^13
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 21:04:46 IST
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somebody plz give me the full soln
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2007 21:33:16 IST
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hey i got it put x=atanp then u get [ 0] [ pi/2] asec 2p dp/a 14(sec 2p) 7 .....
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