|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 12:39:49 IST
|
|
|
how to find the integral of (secx)^2.(cosecx)^2
|
|
|
|
|
|
|
|
Note. I have left out dx in every integral. Too bored to type
^{2}({cosecx})^{2})
=
^{2}%2B({cosx})^{2})/%20(({sinx})^{2}%20({cosx})^{2})
=
^{2}%20%2B%20\int({cosecx})^{2})
= tanx - cotx + c
|
this reply: 15 points
(with 3 
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
15 May 2008 12:53:49 IST
|
|
|
|
this reply: 10 points
(with 2
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
