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a4asd (334)

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what is the intigral of
 
                   cos2x/(1+tan2x)
 
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aditya_arora04 (1077)

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Well,
 
Here is the solution :
 
when you arithematically solve it you get cos4x.
 
Now,  
 
          cos4x
=>      (1+cos2x)2 / 4     
=>      (1 + cos22x + 2cos2x)
=>      [1 + cos2x + (1+cos4x)/2 ] /4
 
now, you can well integrate cos2x and cos4x easily !!!!!
 
you will get your answer !!!!!!!
 
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thevyzz (332)

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easy
put sec^2 x = 1+ tan^2 x
so, it becomes
integral cos^4 x
now integrate
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dinesh_ddt (163)

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spideyunlimited (4223)

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cos4x
= cos2x(1 - sin2x)
put 1 - sin2x = t
 
 
 
 

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- Gaurav Ragtah (spideyunlimited)
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cos4x dx
=(1+cos 2x)^2/4 dx
=1/41+2 cos 2x +cos ^2x dx
=1/4[1 dx +2cos 2x + 1/2 1 +cos 4x]
then we can integrate these simple terms and obtain the required result.

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a4asd (334)

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hey this is
cos^2x/(1+tanx)

There are two ways to live: you can live as if nothing is a miracle; you can live as if everything is a miracle.
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