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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Apr 2008 13:35:05 IST
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can u plz integrate the following (salute assured for each and every one who gives the whole solution)
[ 3] sinx ans 3/4(sinx)4/3
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SHREYA |
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12 Apr 2008 13:35:54 IST
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question is (cube root)sinx
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SHREYA |
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12 Apr 2008 13:49:50 IST
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put x = t3
then dx = 3t2 dt
ques becomes
3 t2 . sin t
on solving , u get
- 3 t2 cos t + 6t sint - 6 cos t
substitute the value of t and get the ans
rate me
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12 Apr 2008 13:54:51 IST
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hey cmon check this and rate me
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12 Apr 2008 14:34:44 IST
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U read it wrong it is not sin(cube root)x but (cube root)sinx
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>>sugeet->
--catalysingsuccess |
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12 Apr 2008 14:38:19 IST
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oh sorry
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12 Apr 2008 14:41:59 IST
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take t3= sinx
ans will come easily
am I right????
rate if correct
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>>sugeet->
--catalysingsuccess |
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12 Apr 2008 15:02:44 IST
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read fast , and give ur salute , I think i am correct
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>>sugeet->
--catalysingsuccess |
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12 Apr 2008 15:11:57 IST
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let sinx = t3
then cosx dx = 2 t2 dt
it becomes
[ ] [ ] t X (2 t2/[ ] 1 - t6 ) dt
= 2 [ ][ ] t3 /[ ] 1 - t6 dt
now let t3 = z
it can now be solved easily
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