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Integral Calculus

Cool goIITian

Joined: 31 Oct 2007
Post: 30
1 Nov 2007 21:33:28 IST
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Indef Integration
None

 

dx/(sin(x-a)sin(x-b)sin(x-c))
 
Note : sin(x-a).sin(x-b).sin(x-c) all are in denominator
Pl give me reply soon.I sent before also, but nobody gave me the answer


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Pratik Anand's Avatar

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Joined: 11 Jun 2007
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1 Nov 2007 22:00:01 IST
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multiply and divide by sin((x-a)-(x-b).  i.e. by sin(b-a) and it will reduce to ur known forms............... NCERT Q , right?
Nadeem's Avatar

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Joined: 25 Aug 2007
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1 Nov 2007 22:38:57 IST
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@pratikanand
Can't u c that there is a sin(x-c)  ?
Pratik Anand's Avatar

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Joined: 11 Jun 2007
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1 Nov 2007 22:52:41 IST
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think that i missed that part . soooooooooooorry..

but lemme try this again
puneet's Avatar

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Joined: 19 Oct 2006
Posts: 1966
7 Nov 2007 02:37:19 IST
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hey
 
no .. continue this way only and then put x-c = t ..
 
we get parts which are integrable ..
 
cheers
 
astrojith's Avatar

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Joined: 5 Jun 2007
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8 Nov 2007 20:34:21 IST
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I didn't get it at all :(



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