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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Mar 2008 15:54:43 IST
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1)  1.tan^2(1/x)dx/x^2 2) sin^2/3x cos^3x dx thank you............
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1 Mar 2008 17:06:10 IST
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[tan 2(1/x)]/x 2 dx 1/x = t -1/x2 dx = dt - tan 2(t)dt [1 - sec 2(t) ]dt = t - tant + c = 1/x -tan(1/x) +c
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this reply: 7 points
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1 Mar 2008 17:22:51 IST
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integral
sin^2/3(x) cos^3x dx
sinx = t
cosx dx = dt
= t^2/3 (1-t^2) dt
t^2/3 dt - t^8/3 dt
3/5 sin^5/3 x - 3/11 sin^11/3 x + c
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this reply: 7 points
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