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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Aug 2007 11:59:00 IST
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if [ ] [ ] (sin -1x) 2dx = x 3{Q(logx) 2 - Rlogx +L} +c, then Q=?, R=?, L=?
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22 Oct 2007 05:56:18 IST
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If we apply by parts we get :
 (sin-1x)2.dx = x.(sin-1x)2 + 2( 1-x2).sin-1x - 2x + c
But the expression given on RHS doesn't matches the above expression.
So differentiate both sides and then put three different values of x so as to obtain three different equations in three variables (Q,R,L) and solve them to find Q,R,L. Its simple but lengthy.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 5 points
(with 1 
in 1 votes ) [?]
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