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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 18:21:29 IST
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evaluate integral :- sq.root of sinx
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 18:29:11 IST
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Hi Guys I am working on other method for it. Will put up the solution soon. Cheers!
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Act..dont just think!!! It saves u time.... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 18:34:53 IST
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listen kiran,on differentiating ur answer ,we dont get sqr root (sinx).so it is wrong cheers !!!
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 18:34:56 IST
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u r wrong this is not just a fn that u can evaluate as such sqrt sinx is a function in a function just differentiate ur answer and u will b able 2 see that u hav gone wrong
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 18:49:12 IST
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take x = sin -1 sinx =  d  =cosx.dx d  /cosx = dx evaluate further and get the answer
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 19:07:22 IST
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 sinx =t cosx dx/2  sinx = dt dx = (2dt  sinx)/cosx dx = 2dt.t/ (1-t4)   sinx .dx =  t. 2dt.t/(1-t 4) =  2t 2dt/(1-t 4) resolve into partial fractions and then integrate if u found ma solution useful plzzzzzzz rate me...... i'll work it out and post the solution soon cheeeers
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 19:07:51 IST
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hay, it is y=sinx^1/2 ¬ y=sinx
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 19:08:29 IST
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okay,i got it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 19:11:41 IST
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can u post ur solution more clearly vineetnsb i'm not able to understand ur solution
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 20:08:34 IST
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First of all
sin x is not a integrable function at all u can check any book or consult with the experts
on integrating as shown above 1 gets some answer but on differentiating again you don't get back sin x
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The difference between genius and stupidity is that genius has its limits.
~ Albert Einstein |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Mar 2007 21:05:46 IST
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The function is not integrable as far as Syllabus upto class XII CBSE is concerned
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Mar 2007 16:40:56 IST
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dude but try integrating tht function u'll never get the answer syllabus is not wat is concerned here the unslovability of integral matter u cannot integrate sqrt sinx indefinitely
the above solution is also wrong
after substituion it should b sinx =t cosx = ] 1-t4
sin x = 2t2 dt/( 1-t4 )
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The difference between genius and stupidity is that genius has its limits.
~ Albert Einstein |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Mar 2007 17:49:44 IST
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Well.. yes.. it is not integrable.... within the limits of theorems we have read...
if you r interested in research, you may try to integrate using complex no.s (although better do it after JEE... its not in syllabus)
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Sudeep Kumar
(B tech, IITd)
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