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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Dec 2007 09:03:50 IST
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0 2 x (2-x)
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iitaspirant001@yahoo.com |
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8 Dec 2007 09:16:58 IST
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pls respond!
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iitaspirant001@yahoo.com |
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8 Dec 2007 11:30:59 IST
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use a-x property....
it beomes integral (2-x) .root(x)
now its easy to integrate.
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8 Dec 2007 22:19:37 IST
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one more method use 2-x = t2 therefore x=-t2+2 dx = -2tdt [ 0] [ 2](t2+2)t(-2tdt) =[ 0][ 2] -2(t 4+2t 2)dt = -352/15 am i correct i not plz tell me
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