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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: integrals
Forum Index -> Integral Calculus like the article? email it to a friend.  
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amulye (180)

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Olaaa!! Perrrfect answer. 34  [39 rates]

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    dx/x^3(x-1)^1/2 = (x-1)^1/2 (3x+2)/4x^2 +K tan^(-1)rt(x-1) +C
 
den d value of K is
 
ans: 3/4
 
if polynomials P & Q satisfies
 
 
    [(3x-1) cosx +(1-2x)sinx]dx =Pcosx +Qsinx
 
ignoring d constant of integration den
 
ans P=3x-2
 
 
 
 
 
 

its time fr u to achive d goal wake up donot hesitate to do hard work
    
Greatdreams (3220)

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Olaaa!! Perrrfect answer. 612  [692 rates]

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1st problem is  nice I will tell you the general way of solving these problems

It is the type of problems where

x m ( a + bx n ) p ,

Now here you have m = - 3 , n = 1 , p = 2

In these type of problems you have, (m+1)/n = an integer , so you can try putting

( a + b x n ) part = t  k  where k is the denominator of the fraction p

now replace it as said and you will see its easy ,

It now reduces to

2 t dt / t ( t2 + 1 )  = 2 dt / (t 2 + 1) 3

Now make required substitutions and get the answer.....this is the approach.


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