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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2008 08:39:45 IST
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integrate w.r.t x
[ ] [ ] x3__ dx..............
2x+1
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lighten up the darkness............
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18 Feb 2008 09:03:36 IST
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put 2x+1=t
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18 Feb 2008 09:53:55 IST
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Just divide the numerator by the denominator and express it in the form dividend=divisor*quotient + remainder, such that it can easily be integrated.
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 x 3/2x+1 dx = 1/8 8x 3/2x+1 dx Numerator = 8x3 = 8x3 + 1 - 1 = (2x+1) (4x2-2x+1) - 1 Hence 8x 3/2x+1 dx = (4x 2-2x+1) dx - 1/2x+1 dx The rest is easy
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Time wounds all heels |
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18 Feb 2008 11:37:04 IST
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Good solution @hsbhatt
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18 Feb 2008 20:15:06 IST
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thanx a lot guyz..............
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lighten up the darkness............
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