Home » Ask & Discuss » Mathematics. » Integral Calculus « Back to Discussion
Integral Calculus
Comments (1)
GAURAV SHARMA
Hot goIITian

Joined: 7 Aug 2007
Posts: 184
26 Nov 2007 11:33:10 IST
Like
1 people liked this
THIS IS DONE BY SUBSTITUTING tanx AS t2,
THEN sec2x dx=2t dt,
sec2x = 1+t4
then the integral becomes
[ ]
[ ] (2t2dt)/ 1+t4
[ ] (2t2dt)/ 1+t4which can be written as
[ ] (t2+1dt)/ 1+t4 +
[ ] (t2-1dt)/ 1+t4i think this becomes easier now....
as tthe above expression is very familiar type of integration.
ALL THE BEST
Reply











