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Integral Calculus

Priyesh's Avatar
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Joined: 18 Feb 2007
Post: 1042
5 Aug 2007 15:54:09 IST
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Integration-1
None

(e^2x - 1)/(e^2x + 1)


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ameya sahasrabudhe's Avatar

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Joined: 17 Jul 2007
Posts: 252
5 Aug 2007 16:28:27 IST
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easy naa yaar?

put e^2x +1 =t

we get integral[(t-2)/2t(t-1) dt]

solve this using partial fractions........

we get
log[(e^2x+1)/(e^x)]

rate if satisfied

Blazing goIITian

Joined: 24 Dec 2006
Posts: 1312
5 Aug 2007 16:28:54 IST
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Put Numerator As :
A(Denominator) + B ( Derivative Of Denominator)
Then Its Very Simple
Neeraj Agarwal's Avatar

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Joined: 22 Jan 2007
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5 Aug 2007 19:45:10 IST
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or write it as...

(e^x - e^(-x) )/(e^x + e^(-x) )

derivative of denomenator is numerator...so answer is log|e^x + e^(-x)| +c
Sagar Saxena's Avatar

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Joined: 8 Oct 2008
Posts: 7221
25 Dec 2009 23:44:41 IST
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hiiiiii

start by putting in the problem  e^2x +1 =t        !!!!!




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