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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Sep 2007 15:01:27 IST
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dx/(cosx+cos )
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Sep 2007 17:23:46 IST
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put cos  =t. since it is constant it wont matter. now convert cosx into half the tangents and put tan(x/20)=z..dis is a substitution and dx will change accordingly.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Sep 2007 17:46:17 IST
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Sep 2007 00:56:17 IST
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[ ] [ ]dx/(cosx+cos ) =[ ] [ ]sec2(x/2)dx/((1-tan2(x/2)+cos (1+tan2(x/2))) Now take tan(x/2)=z as told by aniket. and you will get form of [ ] [ ]dt/(c-at2) which can be solved easily
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 17:00:17 IST
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kkk
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