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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Integration....................
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[Post New]24 Feb 2007 22:16:43 IST
    Subject: Integration....................
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A.Vignesh (124)

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 [ x ( 3x2 + 2x + 1)]-1 dx is
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[Post New]25 Feb 2007 10:35:28 IST
    Subject: Integration....................
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avdesh100 (228)

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look take X^3 common and substitute 1/X=t........
then ull be able to solve it!!!!!!!
will make it BIG!
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[Post New]25 Feb 2007 10:37:50 IST
    Subject: Integration....................
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ruhi (603)

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it can b done by partial fraction
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[Post New]25 Feb 2007 10:45:44 IST
    Subject: Re:Integration....................
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ruhi (603)

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[ ][ ] dx/x(3x2+2x+1)
by partial fraction we get.......
1/x(3x2+2x+1) = 1/x + -3x-2/3x2+2x+1
[ ][ ] dx/x - [ ][ ] (3x+2)dx/3x2+2x+1
hope u got it...............
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[Post New]26 Feb 2007 12:16:07 IST
    Subject: Re:Integration....................
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A.Vignesh (124)

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Thank you very much.
OUR GREATEST WEAKNESS IS GIVING UP ; THE SUREST WAY TO SUCCESS IS ALWAYS TO TRY JUST ONE MORE TIME
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