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sabya_sachi (0)

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Integrate w.r.t x
 
1/  ( sinx + xcosx)  dx

    
ruhi (603)

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hey some one plz try out this ques. its a gud one..............
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KAB (1669)

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We know sinx=(eix-e-ix)/(2i) and cosx=(eix+e-ix)/2
So given integral is
 2idx/((eix-e-ix)+xi(eix+e-ix)
=2iexdx/(e2ix(1+xi)+(xi-1))
Put eix=t
ieixdx=dt
So =2dt/(t2(logt+1)+(logt-1))
Can anyone help me from here.Also tell me whether this is the right approach or not!!!

ADARSH
NITK Surathkal

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madhuri_goteti (27)

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wat u did is rite kab

TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

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ruhi (603)

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hey kab i think now we ve 2 apply by parts................but it will b very complicated
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madhuri_goteti (27)

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kab heres salute for u

TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

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KAB (1669)

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Thanks.May be there is another method.Experts plz help!!!

ADARSH
NITK Surathkal

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ruhi (603)

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sumone plzzzz try this ques
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ruhi (603)

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madhuri how do u know that the kab's soln is correct...............ques is nt solved yet................but its a gud try by kab
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madhuri_goteti (27)

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that is a very good try isn't it??

TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

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sabya_sachi (0)

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substituting further from kab's soln  log t  = u
1/t = du/dt this gives  integ of  2 e ^u du  /  e^u *( e^2u -1 ) + u (e^2u + 1 )
 
now can any one help how to go further
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amar.gupta (590)

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Dear sabya_sachi
 
please check and conform whether it is a definite integral or indefinite. if definite please give the limits too.
 
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