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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Integration
Forum Index -> Integral Calculus like the article? email it to a friend.  
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m.viddya (101)

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Olaaa!! Perrrfect answer. 19  [22 rates]

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Q (tan(1/x) /x )2dx
 
 
1.x-tanx+c
 
2.1/x-tan(1/x)+c
 
3.1/x+tan(1/x)+c
 
4.x-tan(1/x)+c
 
 
    
uday_zingtudor (931)

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Olaaa!! Perrrfect answer. 155  [233 rates]

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Write the integral as [sec2(1/x) - 1]/x2
 
                               = (1/x2)sec2x - 1/x2

Now u can easily integrate this and the answer is 1/x - tan(1/x)

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