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Integral Calculus

New kid on the Block

 Joined: 6 Jan 2009 Post: 20
6 Jan 2009 22:06:45 IST
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integration of
Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Integral Calculus

integration of

New kid on the Block

Joined: 6 Jan 2009
Posts: 20
6 Jan 2009 22:10:04 IST
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integration of 1/{sin x(2+cos x)}

Cool goIITian

Joined: 30 Nov 2008
Posts: 49
6 Jan 2009 22:18:03 IST
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1/{sin x(2+cos x)}

convert sinx and cosx in terms of tan(x/2) and then solve it.

my editor is not working properly so sorry for the interuption.

all the best for your exams.

New kid on the Block

Joined: 27 Dec 2008
Posts: 18
6 Jan 2009 22:54:16 IST
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my friend , i have already tried this method but i got wrong answer ;
the corrrect answer is :1/6 log |1-cos x|-0.5 log |1+cos x|+1/3 log|2+cos x|;
so please give me whole solution;
so that i will point for you

New kid on the Block

Joined: 6 Jan 2009
Posts: 20
6 Jan 2009 23:12:29 IST
0 people liked this

my friend , i have already tried this method but i got wrong answer ;
the corrrect answer is :1/6 log |1-cos x|-0.5 log |1+cos x|+1/3 log|2+cos x|;
so please give me whole solution;
so that i will point for you

Cool goIITian

Joined: 30 Nov 2008
Posts: 49
6 Jan 2009 23:28:24 IST
0 people liked this

1/{sin x(2+cos x)}

={1+tan^2(x/2)}{1+tan^2(x/2)}/{2tan(x/2)/1+tan^2(x/2)}{2+2tan^2(x/2)+1-tan^2(x/2)}

take tan(x/2)=t  that implies {sec^2(x/2)}/{2}dx=dt

=(1+t^2)dt/(t)(3+t^2)

now use partial fraction to get the answer.i got it.

try to get it.even though your answer does not match with that given in the book.don't wory as there can be more than one answer for same question.

all the best for your exams.

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