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Integral Calculus

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24 Oct 2007 22:59:38 IST
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integration offfffffffffffff
None

  of odd powers of sin and cos


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Aditya Arora's Avatar

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Joined: 3 Dec 2006
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24 Oct 2007 23:06:15 IST
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Well, as you go higher, it would be difficult to solve indefinite integrals. but definite integrals can be solved easily.
 
For eg:
 
 
[ ][ ] sin15x dx
 
[ ][ ] sin14x*sinxdx
 
[ ][ ] (1-cos2x)7 sinxdx
Put t = cosx ......................... Eq. 1
 
differentiate both sides
 
dt = -sinxdx
 
So,
 
[ ][ ] -(1-t2)7 dt
 
Now you will have to open the polynomial and then solve it
ram kumar's Avatar

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25 Oct 2007 21:58:19 IST
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hints to evaluate (sinx)^m*(cosx)^ndx  where m and n  are natural numbers

(i) if m is odd  put cosx = t
(ii) if n is odd put sinx=t
(iii)if both m and n are odd you can substitute either sinx=t or cosx=t
(iv) if both m and n are even use trigonmetric identities
(v) if m and n are rational numbers and (m+n-2)/2 is a negative integer , then substitute cotx=t or tanx=t

i hope you are clear with my reply!!

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26 Oct 2007 20:54:03 IST
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[ ][ ] x2--1
------------------
x4+3x2+1



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