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ananth_patri (595)

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Find the value of  -13 { lx-2l + [x] }.. where {} and [] denotes fractional and step functions of x.....plz answer fast....

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ananth_patri (595)

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some one plz reply..

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Anup (157)

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can give u the method write the fractional part as (|x-2|+[x])-[|x-2|+[x]]
now keep splitting the intervals nd integrate .........
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netkid07 (2009)

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is the answer....4 ?

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and 47 other dangerous words.............

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akhil_o (2709)

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is it 7?

we use greatest integer function on a linear function
also after removing a function from GIF, slope of graph due to that =0
so the function takes slope equal tto that of second function (in this case 1)
it is discontinuous at all integral function
so we split into parts

-1->0
GIF=-1, |x-2| goes from 3->2
so f(x) goes from 2->1

0->1
GIF=0, |x-2| goes from 2->1
so f(x) from 2->1

1->2
GIF=1
|x-2| goes from 1 to 0
so f(x) from 2->1

2->3
|x-2| from 0 to 1
GIF=2
so f(x) from 2 to 3

so now we have 4 trapeziums in the graph
area= 1+0/5+1+0.5+1+0.5+2+0.5
=7




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ananth_patri (595)

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did u take [x-2] well thts actually mod x-2....

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akhil_o (2709)

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i took mod (x-2) ...sorry for the wrong symbols..
i meant it was |x-2|
stoill values r same

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amulye (180)

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hey wats d ans is it 0 yaar tell me if im rite den tell m e i wud giv d soln 4 it

its time fr u to achive d goal wake up donot hesitate to do hard work
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ananth_patri (595)

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@ akhil_o solved it rite.....

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