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Integral Calculus

Blazing goIITian

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1 Oct 2008 16:40:55 IST

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integration sum.. need help..

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vignesh the cooler version of newton

Blazing goIITian

Joined: 16 Mar 2008

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2 Oct 2008 17:47:18 IST

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hey guyzzz plzz help..

Mirka

Blazing goIITian

Joined: 13 Aug 2008

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2 Oct 2008 17:56:47 IST

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divide by cos cube x.
Then substitute z = tanx.
u get the ans.

vignesh the cooler version of newton

Blazing goIITian

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Posts: 1801

2 Oct 2008 20:13:03 IST

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tanx = z will give this equation.. i dont know to do this one either...

Nitish

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Joined: 10 Jul 2008

Posts: 110

2 Oct 2008 21:23:59 IST

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Multiply and divide the integrand by 2(sinx + cosx)

Now,

(sinx + cosx)²= 1 + sin2x

= 2 - (1-sin2x)

= 2 - (sin²x + cos²x - 2sinx.cosx)

= 2 - (sinx - cosx)²

Also,

2 - sin2x = 1 + (1 - sin2x)

= 1 + (sinx - cosx)²

Thus,

Put

Resubstituting t = (sinx - cosx),

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