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Integral Calculus

Blazing goIITian

Joined:	31 Jan 2007
Post:	515

25 Oct 2007 14:39:50 IST

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327

integration!!!(urgent)

None

Q) _{[0 ]}

^{[pie ]} x/a^2cos^2x+b^2sin^2x dx

1/cos(x-a)cos(x-b) dx

just tell me how to go about ,plz dont give the soln.but give the final ans so that i can check it up.

urgent, exam tomorrow

plz reply soon!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Comments (3)

'',' Off to a nu start!!

Blazing goIITian

Joined: 13 Jan 2007

Posts: 1289

25 Oct 2007 19:24:24 IST

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q2:-

write numerator as sin (x-a - (x-b)) & to compensate above write sin(b-a) in denominator..

now just open sin formulae taking x-a as 1 & x-b as 2nd angle...

u will see from two terms ,u will get, 1 term got cancelled..& then just apply standard results...u will get it...

Aditya Arora

Blazing goIITian

Joined: 3 Dec 2006

Posts: 1043

25 Oct 2007 19:30:42 IST

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In question 1, take out cos^2x common from denominator and write it as sec^2x, then put t = tanx and then proceed as in substitution.

ram kumar

Blazing goIITian

Joined: 14 Aug 2007

Posts: 407

25 Oct 2007 22:05:13 IST

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the first problem can be solved easily....
apply property 4 to remove the x term from the numerator ......
the divide the numerator and denominator by (cos2x)^2
and put tan2x=t........... you will get the answer easily

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