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Community Discussion Question:
lkjjkl
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Apr 2008 20:33:25 IST
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integrate the following
1/root(3-x2+2x)dx
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SHREYA |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Apr 2008 23:33:53 IST
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see shreya,,,,,,,,,
these type of questions form the basics of integration:
see the solluiton:
I = dx -------------- sqrt [ 4 - (x-1)^2 ]
hope u r easily able to write the above step
now very standard:
see:
let ::::: x-1 = t
dx = dt
so ur:
I = dt --------------- sqrt [ 2^2 - t^2 ]
now easy.... i took alot of space to write thsi que so that u understand it properly
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Apr 2008 13:19:17 IST
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sol: first make perfect square in den. so that the question is converted in to standard form.... so we get ....1/root[(2)^2-(x-1)^2].........................(1)
let x-1 =t differentiate w.r.t x so we get dx=dt....... now apply this to eqn 1 and finally apply formula 1/a^2-x^2dx = 1/2alog(a+x/a-x)....hope i helped u,,,,,,,,,,,
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