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Integral Calculus

Blazing goIITian

Joined:	16 Dec 2006
Post:	424

8 Dec 2007 19:14:48 IST

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NCERT indefinite integral7.6.20

None

Integrate-

{(x-3)e^x /(x-1)³}

Urgent...pls ans!

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sowjanya gudipati

Cool goIITian

Joined: 13 Oct 2007

Posts: 75

8 Dec 2007 22:00:11 IST

Like 1 people liked this

(x-3)e^x/(x-1)³=

(x-1-2)e^x/(x-1)³=

e^x((x-1)-2)/(x-1)³

hey im not using int sign plz tc of that

e^x(x-1)/(x-1)³-2e^x/(x-1)³

=e^x(1/(x-1)²-2/(x-1)³)

know take 1/(x-1)²as a function for which derivative is -2/(x-1)³

so the above int is in the form of e^x(f(x)+(f¹)) fo r which ans will be in the form of e^x(f(x))

therefore ans for above int is e^x/(x-1)²

hope its clear

if not ask me

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