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Forum Index -> Integral Calculus like the article? email it to a friend.  
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KEERU (45)

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  1. the value of 
[ 0][1 ] tan-1  (2x-1 / 1+x-x2 ) dx
             
    
raulrag009 (1194)

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Forgot abt the property
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Nithy (400)

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[ 0][ 1]    f(x) =  [ 0][ 1]  f(1-x) dx

substitute u'll get  it = -f(x)

by that property

ans=0

same concept as in the earlier sum u asked

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priyesh (1586)

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tan-1  (2x-1 / 1+x-x2 )
 
= tan-1 ( (x + (x -1))/(1 - (x(x-1))  =  tan-1(x) + tan-1(x-1)
 
now it can be easily integrated
             

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