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Integral Calculus

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Joined:	28 Feb 2007
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24 Feb 2008 10:15:44 IST

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One last prob

None

Its time you guys devote more time to boards. So this is the last integral: Evaluate

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abhishek sinha

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Joined: 18 Dec 2007

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24 Feb 2008 17:09:58 IST

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write x^2 in the Nr . as x cos x * x sec x

Notice that d/dx( x sin x + cos x ) = x cos x

So take x sec x as the first fn and x cos x / ( x sin x + cos x ) as the 2nd fn and integrate by parts .

U will see that d/dx ( x / cos x ) ( in the 2nd part ) =( cos x + x sin x )sec^2 x

The term in the bracket cancels with the integral previously evaluated .

Lastly put the limits .

Ankit

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Joined: 17 Oct 2007

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15 Feb 2009 20:34:36 IST

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Can we take xsecx as first function?

karan mital

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Joined: 19 Dec 2008

Posts: 41

16 Feb 2009 16:12:55 IST

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is there is any other way to solve the question i stuck here

its not x2 it is 1+tanx whole square and secx whole squre

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