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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: please Integrate it
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nknikhilesh1 (108)

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Olaaa!! Perrrfect answer. 18  [27 rates]

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ankitagg (283)

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SIMPLE;


WRITE it as


integr. (e^logx^9 -e^logx^5)/(e^logx^2 - e^ logx^4) dx      [using property alogx =logx^a]


inte. (x^9 - x^5)/(x^2-x^4)dx                       [e^logx =x]


int.  -x^5(x^4-1)/(x^2-1)dx


int.  -x^3(x^2+1)(x^2-1)/(x^2-1)dx


int. - x^5dx - int. x^3


-x^6/6  - x^4/4  +c


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paddy.dude (1152)

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Olaaa!! Perrrfect answer. 174  [315 rates]

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firstly use the 2 properties


 


 1 .   elog X = X  


  2.   2 log X  = log X 2


using these properties we can modify the integral as


 


=  X9 - X5 /  X2 - X4


take   X2 out from numerator and denominator and cancell them off now we get


= X7 - X3 / 1 - X2


now take   -X3 common from numerator we get


= -X3( 1 - X4 ) / 1 - X2


now write 1 - X4 as ( 1 - X2 )( 1 + X2 )


( 1 - X2 ) cancells with the denominator


we get


= - X3 - X5


= - X4/ 4  -  X6/ 6 + C


 

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