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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 18:25:26 IST
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please integrate (tan-1 x)2:::tan inverse x to the power whole square
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14 Jun 2008 19:14:46 IST
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put tan^-1x = t
now 1/1+x^2dx = dt....
so from question u will get .....=t^2/1+tan^2tdt
= t^2cos^2tdt
=t^2[1+cos2t]/2dt
=[ t^2/2+t^2cos2t/2]dt
=I1+I2
i2 u can solve this by applying by parts,,,,
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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@chinmay,It is not t2/1+tan2t,It is t2(1+tan2t)=t2sec2t.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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14 Jun 2008 19:44:53 IST
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ooooohhhhoooooo u r right ok ok thanks for correcting me,,,a silly mistake ,,neways thanks allamraju....
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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14 Jun 2008 22:06:40 IST
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Perfect answer allamraju. Well done
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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24 Jun 2008 22:52:27 IST
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THANKS CHINMAY AND AALAMRAJA TO HELP ME WID DIS.
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BYEE HOPE TO HAVE A HELP FROM U IN FUTURE ALSO
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