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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Please solve this one....
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nknikhilesh1 (108)

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Evaluate


    
nknikhilesh1 (108)

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Anyone please reply me........

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allamraju (3422)

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Put x=cos2k then dx=-sin2kdk.So,the integral becomes








Where .

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deedee (1951)

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one more substitution u can use 




 






 




 


put x=(cos(2@)^2 




 


thus u get dx=(-2)*(sin2@)




 


and ur integral reduces to




 


write it as




 


u can solve it futher  ............


and multiply by (-1) ......




 


 


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