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divalli_oct07 (156)

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 [0 ][a ] [x/a(a^2-x^2)^1/2]dx

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chimanshu_007 (11528)

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hiii
 
[0 ][a ] [x/a(a^2-x^2)^1/2]dx
 
put
 
a2 - x2 = t2
 
-2xdx = 2tdt
 
xdx = tdt
 
-1/a[0 ][a ] tdt / t
 
=- 1/a l dt l a o
 
 
now u can solve

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krishna.gopal (2289)

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Good work himanshu

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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