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Integral Calculus

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16 Mar 2007 18:18:13 IST

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848

plz help!!!!!!

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Q -) The value of

in the interval [-

,0] satisfying

sin

+ _{[ theta]}^{[2 theta ]} cos 2xdx= 0 is ....................

a)-

/2 b)-

c)-

/3 d)0

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Comments (13)

ankur gupta

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16 Mar 2007 19:06:27 IST

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the ans. is (a) nd (c)
if i m right
tl me then i wl post the logic also

sumit kapoor

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16 Mar 2007 19:06:36 IST

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its ans is 0

ankur gupta

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16 Mar 2007 19:07:27 IST

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ohhhhh
i mean the ans is -pi and -pi/3
i.e (b) and (c)

sumit kapoor

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16 Mar 2007 19:10:47 IST

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sory its ans is b &d

Himanshu

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16 Mar 2007 19:14:57 IST

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nope u all r wrong (little bit)

ankur gupta

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16 Mar 2007 19:17:19 IST

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last time the ans is (b),(c),(d)
thats the final answer.....

Himanshu

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16 Mar 2007 19:18:53 IST

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plz present the ans

Himanshu

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16 Mar 2007 19:19:28 IST

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i mean the sol.

sumit kapoor

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16 Mar 2007 19:21:25 IST

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this time i am sure ans is b c and d but not a

CyBorG

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16 Mar 2007 21:04:48 IST

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After evaluating the integral,

sinQ+(sin4Q-sin2Q)/2=0

So b,c,d are correct

vishak p

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16 Mar 2007 21:06:40 IST

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ya b,c,d are the correct ones !

Shashank Shandilya

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18 Mar 2007 12:20:50 IST

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I think the ans should be b and d.

On solving we get this eq

sin2theta= (-sintheta)

only b & d satisfies the eq.

Jyotibrata Bhattacharjee

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Joined: 20 Mar 2007

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20 Mar 2007 13:09:08 IST

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b ,c,d . satisfy the ans
Hence; b,c,d are right.
plz rate

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