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Integral Calculus

Blazing goIITian

Joined:	4 Nov 2007
Post:	1524

10 Nov 2007 17:50:15 IST

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446

plz integrate this!!!

None

_{[ ]}^{[ ]} x/(1-x²)^1\2

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Comments (4)

joy francis

Blazing goIITian

Joined: 19 Feb 2007

Posts: 1802

10 Nov 2007 18:01:33 IST

Like 1 people liked this

1-x² = t²

-2xdx = 2tdt

xdx=-tdt

integral becomes

-tdt/t

= -

= -t = - (

(1-x²))

Nivedh Iyer

Blazing goIITian

Joined: 5 Jul 2007

Posts: 1236

10 Nov 2007 18:04:29 IST

Like 2 people liked this

let x² = t.....
therefore,
2xdx=dt

xdx/(1-x²)^1/2 =

dt/2(1-t)^{1/2

NOW SOLVE............!!!!!!!!!}

k greatgirl

New kid on the Block

Joined: 23 Oct 2007

Posts: 7

10 Nov 2007 18:38:17 IST

Like 0 people liked this

1-x2=t2
differentiate
-2xdx=2tdt
-xdx=tdt

therefore,

_{[ ]}

^{[ ]} -tdt/t = -

dt =-t = -

(1-x2)

if u r satisfied den plz vote

polymath

Hot goIITian

Joined: 9 Nov 2006

Posts: 150

10 Nov 2007 18:43:46 IST

Like 0 people liked this

or put x=sin

so cos

(1-x²)

dx= cos

the quesn becomes

sin

. d

= -cos

+ c

ie x/(1-x²)¹ = -

(1-x²) + c

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