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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: plz solve this question
Forum Index -> Integral Calculus like the article? email it to a friend.  
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enthalpy (0)

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allamraju (3422)

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Firstly,1+cos3x=4cos3x-3cosx+1

=[4cos3x-2cos2x]+[2cos2x-3cosx+1]

=2cos2x(2cosx-1)+(2cosx-1)(cosx-1)

=(2cosx-1)[2cos2x+cosx-1]

=(2cosx-1)(cosx+cos2x).

So,


MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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