Obtain real solution of the equation

 

xy+3y2-x+4y-7=0

2xy+y2-2x-2y+1=0

Okay

 

So the eqautions are

 

         xy  + 3y² - x + 4y - 7 = 0    ... (1)  

and  2xy  + y² - 2x - 2y + 1 = 0    ... (2)

 

Now 2 * (1) - (2) gives another equation ... 

 

                  5y² + 10y - 15 = 0

  or               y² + 2y - 3 = 0

 

              so y = -1 , 3

 

 Put in equation (1) to get values of x ..

 

Now I have solved this question but u might be guessing how to start ... am i right ?? ha ha ... well the key in such questions in the observation ... my thought process was to eliminate the xy term as it is difficult to solve equations with xy term ... n in the process i reached a quadratic in y ...

 

Always remember .... if there is a solution ...u can reach it .. n small tricks will help ... rite ..

 

cheers