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 Community Discussion Question:
solve
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 20:04:07 IST
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 [(tan x)1/2+(cot x)1/2] dx
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15 May 2008 20:36:27 IST
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%20%2B%20(cotx)}%20=%20sinx%2Bcosx/\sqrt{sinx%20cosx})
/\sqrt{sin%202x})
/%20\sqrt{1-(1-%20sin2x)})
/\sqrt{1-(sinx%20-%20cosx)^2})
%20%2Bc%20;%20you%20\;can%20\;simplify%20\;further%20.)
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15 May 2008 20:38:05 IST
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u take tan x as t and cot x as 1/t and solve
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