$\int$ sin x/sin 3x dx

gokusuper

$\int$ sin x/sin 3x dx

nunoxic

sin 3x = 3 sin x - sin^3x
divide by sin x and then divide by cos^2

nunoxic

u get :

dx / 3 - sin^2 x
Divide by cos^2

sec^2 x dx / 3 sec^2 x - tan^2 x
sec^2 x dx / 3 tan^2 x + 3 - tan^2 x
sec^2 x dx / 2 tan^2 x + 3

tan x = t

dt / 2t^2 + 3

1/root 6 x tan inverse (root 2 x tan x / root 3)

allamraju

Ask & Discuss Questions with Community & Experts

$\int$ sin x/sin 3x dx

I think sin3x=3sinx-4sin³x.Otherwise the method is correct.

Ask & Discuss Questions with Community & Experts

sin x/sin 3x dx

I think sin3x=3sinx-4sin3x.Otherwise the method is correct.

$\int$ sin x/sin 3x dx

I think sin3x=3sinx-4sin³x.Otherwise the method is correct.