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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: solve
Forum Index -> Integral Calculus like the article? email it to a friend.  
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[Post New]15 May 2008 20:58:08 IST
    Subject: solve
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gokusuper (5)

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(cos x-sinx)/(7-9 sin2x) dx
    
[Post New]16 May 2008 11:24:33 IST
    Subject: Re:solve
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allamraju (3090)

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Put cosx+sinx=tdt=(cosx-sinx)dx and t2=1+sin2x.So,the integral becomes

dt/16-9t2=(1/24)lnI3t+4/3t-4I
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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