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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 21:00:08 IST
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 (cos2 x)/(1+tan x) dx
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15 May 2008 21:18:55 IST
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![(4*x + Cos[2*x] + 2*Log[Cos[x] + Sin[x]] + Sin[2*x])/8](http://integrals.wolfram.com/Integrator/MSP/MSP22412178917993707326_1320?MSPStoreType=GIF "See either the Input Form or Output Form for text based results.")
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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15 May 2008 21:19:17 IST
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wait ill put steps
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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16 May 2008 14:07:03 IST
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My ans is
ln(1+tanx)/2+x/2+cos2x/2-ln(sec2x)/4 Tell me whether it is right and if not,what's the ans?
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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16 May 2008 14:12:54 IST
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put tanx = t
ques will be ..integration of 1/1+t dt
this is ln(1+t)
= ln (1+tanx)
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SAIYANS ARE OF TRUE WARRIOR RACE . DONT UNDER-ESTIMATE US!
special theory of relativity ....i luv it...
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16 May 2008 14:14:41 IST
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budokai, it is cos^x on the numerator
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16 May 2008 14:15:47 IST
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sorry ,..i am mistaken
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SAIYANS ARE OF TRUE WARRIOR RACE . DONT UNDER-ESTIMATE US!
special theory of relativity ....i luv it...
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16 May 2008 14:17:08 IST
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budokai u r wrong........when u put tanx = t u will get cos^4x in num.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
      
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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16 May 2008 14:17:10 IST
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Are budokai,the derivative of tanx is sec2x and not cos2x.If it is so,why shud I waste 15min to do that problem.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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16 May 2008 14:22:38 IST
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arre bhai ..kisi se galti nahin ho sakti hai kya
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SAIYANS ARE OF TRUE WARRIOR RACE . DONT UNDER-ESTIMATE US!
special theory of relativity ....i luv it...
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16 May 2008 14:24:11 IST
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Sorry,I didn't notice the above posts.Don't feel bad.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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16 May 2008 14:26:51 IST
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hey allamraju can u give the key idea to solve this,,,,i mean a little bit hint.....
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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16 May 2008 14:46:22 IST
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edit !
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16 May 2008 15:44:39 IST
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The integral is solved as
Put tanx=t dt=sec2xdxcosx=1/rt1+t2
dt/(1+t)(1+t2)2. spliting into partial fractions,we get
(1/2)(1/1+t)+1/2(1+t2)-t/2(1+t2)-t/(1+t2)2 It's integral becomes,
ln(1+t)/2+Tan-1t/2-(1/4)ln(1+t2)+1/2(1+t2).Putting t=tanx,We get,
ln(1+tanx)/2+x/2-ln(sec2x)/4+cos2x/2
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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16 May 2008 15:55:19 IST
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