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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 21:18:33 IST
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 (e3x+ex)/(e4x-e2x+1) dx
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16 May 2008 21:20:31 IST
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edited...
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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16 May 2008 21:22:39 IST
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-e^x/(e^2x-1)
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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16 May 2008 21:24:54 IST
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put e^x =t.
e^dx=dt
now.....(t^2+1)dt/(t^4-t^2+1)
divide by t^2 in both numerator and denominator..
put t-1/t=a...
Vnow finally u get da/a^2...EVALUATE..A ND SUBSITITUTE BACK....
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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