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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: The Beast
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Radon222 (166)

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int  rac{(sqrt{x})^5}{(sqrt{x})^7+x^6},dx

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chemicaltester (428)

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x^5/2 /(x^7/2 + x^6)
put x^7/2 =t
hence 7/2 *x^5/2 dx =dt
also x^6 =x^12/2 = ( x^7/2)^5/2

hence equation becomes

dt /t +t^5/2
=dt/t(1 +t^3/2)
i think we have to further substitue
adjesting numerator as t^1/2 +1 -t^1/2 we can do that

if this gives answer do rate me
if this then somebody please help both of us
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konichiwa2x (2342)

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edit: removed solution on radon's request. Open for others to try.

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

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raulrag009 (1223)

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Here is my solution
 
   \int{\frac{x^{\frac{5}{2}}}{x^{\frac{7}{2}}+x^{6}}}dx\\\\
\int{x^{\frac{-7}{2}}(1+x^{\frac{-5}{2}})^{\frac{-1}{2}}}dx\\\\
Put\;1+x^{\frac{-5}{2}}=t^{2}\\\\
x^{\frac{-7}{2}}dx=\frac{4}{5}tdt\\\\
\frac{4}{5}\int{dt}\\\\
=\frac{4t}{5}+C\\\\
=\frac{4}{5}(1+x^{\frac{-5}{2}})^{\frac{1}{2}}+C
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Radon222 (166)

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rahul your answer is perfect except a small negative sign mistake in the end

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