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Integral Calculus
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venkat v.t
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Joined: 7 Aug 2007
Posts: 244
28 Oct 2007 14:12:44 IST
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d/dx(xsinx+cosx)=x cosx
I=Integral of (x/cosx) (x cosx/[x sinx+cosx]2) dx
Integrating byparts
I =(x/Cosx) (-1/x sinx+cosx) + Integral of (xsinx+cosx)/cos2x. 1/xsinx+cosx
and proceed .we get
(Sinx-x cosX)/(x sinx+cos x)+C
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