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Integral Calculus

Hot goIITian

Joined:	9 Sep 2007
Post:	130

1 Dec 2007 12:55:34 IST

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465

very easy ques (plzzz solve) rates assured

None

find integration of the following wrt X

(sin^3x + cos^3x)/(sin^2x cos^2x)

I am very new at integration

plz tell me the general things to be kept in mind while solving integration!!!!!plzzzzzzzzz

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Comments (2)

aditi garg

Scorching goIITian

Joined: 2 Nov 2007

Posts: 288

1 Dec 2007 15:44:36 IST

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take both the terms separately...
sin x/cos^2x + cos x/ sin^2x
=now for the first part u take cos x = t
and thn for the second part u take sin x = t...
and in both cases u have their derivatives in trhe numerator...
i hope now u will be able to solve it
the answer will be
sec x - cosec x
rate me if it helps u

sowjanya gudipati

Cool goIITian

Joined: 13 Oct 2007

Posts: 75

1 Dec 2007 17:29:11 IST

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no need for going ny substituation u can directly use

_{[ ]}

^{[ ]} sinx/cos2x=_{[ ]}

^{[ ]} tanxsecx=secx

_{[ ]}

^{[ ]} cosx/sin2x=_{[ ]}

^{[ ]} cotxcosecx=cosecx

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