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Integral Calculus

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30 Oct 2007 08:41:40 IST

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670

Very Good Integration Question(rates to all correct replys)

None

Ques-_{[ 0]}

^{[pie/6 ]} ((

3cos2x - 1)/cosx)dx

Answer will be posted after 5 or more Replys.

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Comments (10)

Anupam Agarwal

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30 Oct 2007 19:45:00 IST

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Please someone solve this.

Sameer Bhatt

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30 Oct 2007 20:17:54 IST

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sin^-1^{[ ]}

2(2-^{[ ]}

3)/ 3^{[ ]}

3} -1/3

Sameer Bhatt

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30 Oct 2007 20:20:23 IST

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2pi/90 - 1/3

Anshuman Bhujabal

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1 Nov 2007 06:07:09 IST

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Hey my answer comes out to be

3 - (1+

3)ln

Please rate if it's correct......

astrojith

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8 Nov 2007 20:55:16 IST

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My answer is :

3 - log

3

Please rate if it is correct. :)

richa sharma

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8 Nov 2007 21:00:19 IST

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abhujabal is correct...the answer is

3-(1+

3)ln

Anshuman Bhujabal

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9 Nov 2007 06:12:08 IST

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hey thanx richa
plz someone rate ....
where is anupamagarwal she said to rate the correct repies.....

astrojith

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9 Nov 2007 22:29:29 IST

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abhu ma' man, could you please post the idea for solving it too ? Thats the point of being here, right ? Sharing knowledge. :)

Anshuman Bhujabal

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10 Nov 2007 06:46:35 IST

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OK my friends I am giving the solution First break cos2x as 2cos²x - 1

We get

_{[ ]}

^{[ ]} (2

3cos²x-

3-1)/cosx dx

= _{[ ]}

^{[ ]} 2

3cosx dx - (

3+1)_{[ ]}

^{[ ]} secx dx

3sinx |₀^/6- (1+

3)ln(secx + tanx) |₀^/6

⁼

3 - (1+

3)ln

I hope now u r satisfied........

I hopw I can expect some points now......

k greatgirl

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Joined: 23 Oct 2007

Posts: 7

10 Nov 2007 18:49:22 IST

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hi ma answer is

3-(1+

3)ln

3

plz rate if correct ok BYE
ALL D BEST FOR UR FUTURE

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