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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: what are the shortcuts in integrals?
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roysasi (0)

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what are the shortcuts in integrals?
    
waterdemon (5140)

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I hope these prove useful for you.

1)f(ax+b) 
put (ax+b)=t
 
2)px+q/ax2+bx+c
 
take px+q=L(differentiation of ax2+bx+c) + m
 
Find values of L and m and substitute them in the exp.
 
and divide the whole by (ax2+bx+c) and now you can do
 
its integration easily as it is divided in two parts.
 
3)P(x)/ax2+bx+c
 
In such cases we divide the numerator by denominator
 
and then express as
 
Q(x) + [R(x)/ax2+bx+c]
 
Here Q(x) = Quotient after dividing.
and  R(x) = Remainder after dividing.
 
This becomes Q(x).dx + R(x)/ax2+bx+c .dx
 
4)px+q/(ax2+bx+c)1/2
 
Take px+q = l(Diff. of Denominator) + m
 
Find values of "L" and "m" and solve.
 
After this take x common and make the coefficient of x2
 
as unity.
 
Now add and substract the square of half of the
 
coefficient of x.
 
Now apply formula to get the answer.
 
5) 1/aSinx+bCosx , 1/a+bSinx , 1/a+bCosx.dx
 
We proceed as follows.
 
Take Sinx = 2 Tan x/2 / 1+tan2x/2 or
 
Take Cosx = 1-tan2x/2 / 1+tan2x/2
 
Replace 1+tan2x/2 in numerator by sec2x/2.
 
put tan x/2 = t as 1/2Sec2x/2.dx=dt 
 
And solve.
 
6)1/aSinx+bCosx
 
We take a=rCos@ and b=rSin@
 
as  r=(a2+b2)1/2.@=tan-1(b/a)
 
Now solve.
 
7)aSinx+bCosx/cSinx+dCosx
 
Numerator=l(Diff. of Denominator) + m(denominator)
 
Get value of L and m and solve.
 
8)aSinx+bCosx+c/pSinx+qCosx+r
 
Here c and r = Integers(constants)
 
Num=L(den.)+m(Diff. of Den.)+ n
 
Find values of L,m,n and then take the form as:
 
aSinx+bCosx+c/pSinx+qCosx+r
 
=L.dx + mDiff. of Den/Den. + n1/pSinx+qCosx+r
 
Now solve.
 
9)f'(x)/f(x).dx = log{f(x)}
 
10)ex{f(x)+f'(x)}.dx = ex{f(x)} + c
 
11)(px+q)(ax2+bx+c)1/2.dx
 
px+q=L(Diff. of ax2+bx+c)+m
 
Find L and m and solve.
 
12)h(x)/P(Q)1/2.dx
 
P and Q are linear.
put Q =t2.
 
Got example of a form.
 
a)1/(ax+b)(cx+d)1/2.dx
 
put (cx+d)=t2.
 
b)P is quadratic and Q is linear
 
1/(ax2+bx+c)(dx+e)1/2.dx
 
put (dx+e)=t2.
 
c)P is linear and Q is Quadratic.
 
1/(ax+b)(cx2+dx+e)1/2.dx
 
put (ax+b)=1/t
 
d)P and Q both are Quadratic.
 
1/(ax2+b)(cx2+d)1/2.dx
 
put x=1/t and then c+dt2 = u2.
 
Hope you find it useful.
 
Rate me if useful.
 
Cheers!!!!!!!!!!!

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astrojith (131)

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Dude, nice resource. But I didn't quite understand 5th,6th and 12(D)th points.

I think it'll be much more understood if you can either use some formatting or explain it further with an example problem.

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