I hope these prove useful for you.
1)
f(ax+b) put (ax+b)=t
2)
px+q/ax2+bx+c
take px+q=L(differentiation of ax2+bx+c) + m
Find values of L and m and substitute them in the exp.
and divide the whole by (ax2+bx+c) and now you can do
its integration easily as it is divided in two parts.
3)
P(x)/ax2+bx+c
In such cases we divide the numerator by denominator
and then express as
Q(x) + [R(x)/ax2+bx+c]
Here Q(x) = Quotient after dividing.
and R(x) = Remainder after dividing.
This becomes
Q(x).dx +
R(x)/ax2+bx+c .dx
4)
px+q/(ax2+bx+c)1/2
Take px+q = l(Diff. of Denominator) + m
Find values of "L" and "m" and solve.
After this take x common and make the coefficient of x2
as unity.
Now add and substract the square of half of the
coefficient of x.
Now apply formula to get the answer.
5)
1/aSinx+bCosx ,
1/a+bSinx ,
1/a+bCosx.dx
We proceed as follows.
Take Sinx = 2 Tan x/2 / 1+tan2x/2 or
Take Cosx = 1-tan2x/2 / 1+tan2x/2
Replace 1+tan2x/2 in numerator by sec2x/2.
put tan x/2 = t as 1/2Sec2x/2.dx=dt
And solve.
6)
1/aSinx+bCosx
We take a=rCos@ and b=rSin@
as r=(a2+b2)1/2.@=tan-1(b/a)
Now solve.
7)
aSinx+bCosx/cSinx+dCosx
Numerator=l(Diff. of Denominator) + m(denominator)
Get value of L and m and solve.
8)
aSinx+bCosx+c/pSinx+qCosx+r
Here c and r = Integers(constants)
Num=L(den.)+m(Diff. of Den.)+ n
Find values of L,m,n and then take the form as:
aSinx+bCosx+c/pSinx+qCosx+r
=
L.dx + m
Diff. of Den/Den. + n
1/pSinx+qCosx+r
Now solve.
9)
f'(x)/f(x).dx = log{f(x)}
10)
ex{f(x)+f'(x)}.dx = ex{f(x)} + c
11)

(px+q)(ax
2+bx+c)
1/2.dx
px+q=L(Diff. of ax2+bx+c)+m
Find L and m and solve.
12)

h(x)/P(Q)
1/2.dx
P and Q are linear.
put Q =t2.
Got example of a form.
a)

1/(ax+b)(cx+d)
1/2.dx
put (cx+d)=t2.
b)P is quadratic and Q is linear

1/(ax
2+bx+c)(dx+e)
1/2.dx
put (dx+e)=t2.
c)P is linear and Q is Quadratic.

1/(ax+b)(cx
2+dx+e)
1/2.dx
put (ax+b)=1/t
d)P and Q both are Quadratic.

1/(ax
2+b)(cx
2+d)
1/2.dx
put x=1/t and then c+dt2 = u2.
Hope you find it useful.
Rate me if useful.
Cheers!!!!!!!!!!!
