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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: (x3+x2+x-1)/(x2-1)[(2-x2)1/2] dx
Forum Index -> Integral Calculus like the article? email it to a friend.  
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[Post New]16 May 2008 18:58:30 IST
    Subject: (x3+x2+x-1)/(x2-1)[(2-x2)1/2] dx
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gokusuper (5)

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Olaaa!! Perrrfect answer. 1  [1 rates]
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(x3+x2+x-1)/(x2-1)[(2-x2)1/2] dx
    
 
Forum Index -> Integral Calculus
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