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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2008 22:54:49 IST
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Can anyone prove that 2=1.
It seems to be impossible na........?
Lets see if u all can?
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13 Feb 2008 23:00:46 IST
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Given x = 1 and y = 1, then
x = y
Multiplying each side by x,
x2 = xy
Subtracting y2 from each side,
x2 - y2 = xy - y2
Factoring each side,
(x + y)(x - y) = y(x - y)
Dividing out the common term, (x - y) results in
x + y = y
Substituting the values of x and y,
1 + 1 = 1
or
2 = 1
"Q.E.D."
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13 Feb 2008 23:03:07 IST
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Nice on there sniper...
dividin by (x-y) is as simple as dividin by 0
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13 Feb 2008 23:03:25 IST
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AS X = Y ,
u get
x - y = 0
u cant cancel zero both sides dude
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13 Feb 2008 23:05:04 IST
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-2 = -2
4 - 6 = 1 - 3
4 - 6 + 9/4 = 1 - 3 + 9/4
(2 - 3/2)2 = (1 - 3/2)2
2 - 3/2 = 1 - 3/2
2 = 1
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" The difficult we do immediately, impossible takes a little longer "
--- U.S. Army
"It's better to have a gun and not need it than to need a gun and
not have it."
--- The Sniper
"You can get more with a kind word and a gun than you can with a
kind word. "
--- The Sniper
"Join the Army: travel to exotic distant lands; meet exciting,
unusual people and kill them. "
--- The Sniper
"The victor will never be asked if he told the truth."
--- Adolf Hitler
"Stop talking, start doing"
--- IBM
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13 Feb 2008 23:08:42 IST
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well done sniper,
I would recommend himanshu to see this video on youtube.
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13 Feb 2008 23:10:30 IST
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kx = x + x + ... + x (k-times) .......................[1]
xx = x + x + ... + x (x-times) .......................[2]
x^2 = x + x + ... + x (x-times) .......................[3]
dx(x^2) = 2x (diff. wrt x) ................................[4]
dx(x + x + ... + x) = 1 + 1 + ... + 1 (x-times) ...........[5]
so
2x = 1 + 1 + ... + 1 (x-times) {from eq. [4],[5]} ....[6]
so we have
2x = x ................................................[7]
so
2 = 1
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" The difficult we do immediately, impossible takes a little longer "
--- U.S. Army
"It's better to have a gun and not need it than to need a gun and
not have it."
--- The Sniper
"You can get more with a kind word and a gun than you can with a
kind word. "
--- The Sniper
"Join the Army: travel to exotic distant lands; meet exciting,
unusual people and kill them. "
--- The Sniper
"The victor will never be asked if he told the truth."
--- Adolf Hitler
"Stop talking, start doing"
--- IBM
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13 Feb 2008 23:14:04 IST
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Ah there my friend lies the folly.
The folly of reducing a quadratic to a linear expression !
(2 - 3/2)^2 = (1 - 3/2)^2
actually on solving it, you don't get
2 - 3/2 = 1 - 3/2
what you get is:
2 - 3/2 = 3/2 - 1
1/2 = 1/2
See that's the mistake of simply cancelling square power to reduce to linear!
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* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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13 Feb 2008 23:15:22 IST
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Also differentiation is not defined for discreet quantities like x + x + x + x + x ......
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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13 Feb 2008 23:17:46 IST
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I was only solving his doubt dudes...... :-)
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" The difficult we do immediately, impossible takes a little longer "
--- U.S. Army
"It's better to have a gun and not need it than to need a gun and
not have it."
--- The Sniper
"You can get more with a kind word and a gun than you can with a
kind word. "
--- The Sniper
"Join the Army: travel to exotic distant lands; meet exciting,
unusual people and kill them. "
--- The Sniper
"The victor will never be asked if he told the truth."
--- Adolf Hitler
"Stop talking, start doing"
--- IBM
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13 Feb 2008 23:29:20 IST
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I didn't understood what u said spidey.
?????????????????????????????
(2 - 3/2)^2 = (1 - 3/2)^2
actually on solving it, you don't get
2 - 3/2 = 1 - 3/2
what you get is:
2 - 3/2 = 3/2 - 1
1/2 = 1/2
????????????????????????????
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13 Feb 2008 23:37:12 IST
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yes quadratic!
because (a-b)^2 = (b-a)^2.............. this is true
but this doesnt imply
a - b = b - a
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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13 Feb 2008 23:43:17 IST
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But whats the mistake in the first reply in terms of x and y?
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14 Feb 2008 00:12:44 IST
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in the very first reply?
look at first statement/assumption
x = |
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