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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: 3 salutes assured...........
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kishan12 (309)

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Two parallel wires carry equal currents of 10A along the same  direction and are seperated by a distance of 2cm.Find the magnetic field at a point which is 2cm away from each of these wires.
 
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rhd92781 (686)

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r u getting of which point this question speaks about?
both wires r 2cm frm each other
any point which is 2 cm frm one shall be either 4 cm frm other or shall lie on the other

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rhd92781 (686)

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got it i think!
B=u/2pi i/a
B=u/2pi 10/(0.02)
2 wires will have two B's at an angle of 120 degrees
so the resultant is root(B^2+B^2+2B^2cos120)

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I will not refuse to do the something that I can do.
- Edward Everett Hale
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kishan12 (309)

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Dude this is in HCV
pg250
Q:10
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rhd92781 (686)

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oops!
did a mistake
they will be at 60 degrees
so B=u/2pi 500root(3)

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I am only one,
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And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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kishan12 (309)

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Dude..........see the angle wud be 60 and not 120.........equilateral triangle formed...........................and ya got the ans. Thanks
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kishan12 (309)

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shit didnot see your reply!!!!!!
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spideyunlimited (3083)

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is the answer = (5.root(3) / 0.02) * u / pi Tesla ?
just added cos components of fields. sin components cancel out. so 2 * cos component of any one's field.


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rhd92781 (686)

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frnd u have got a big big big heart 3 salutes!

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I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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